Answer:
x-intercepts are (-3,0) and (-4,0).
y-intercept is (0,12).
Step-by-step explanation:
x-intercept is a point where the value of y is zero.
y-intercept is a point where the value of x is zero.
Given equation is :
y=x²+7x+12
put x=0 in given equation to find y-intercept.
y=(0)²+7(0)+12
y= 0+0+12
y= 12
hence, y-intercept is (0,12).
put y=0 in given equation to find x-intercept.
0=x²+7x+12
split the middle term of above equation to make the equation into two groups such that the sum of two numbers should be 7 and their product be 12.
x²+3x+4x+12=0
making two groups and taking common out:
x(x+3)+4(x+3)=0
take (x+3) common,
(x+3)(x+4)=0
x+3=0 or x+4=0
x=-3 or x=-4
hence, x-intercepts are (-3,0) and (-4,0).
