Question

In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the system if the initial energy was 2000 j?
1. write the equation
2.list out your known variables
3.plug the numbers into the equations
4.Solve
5.write your solution statement that includes initial energy and final

Answer 1

Answer:

2500 J

Explanation:

The first law of thermodyniamics states that:

$\Delta U = Q-W$

where

$\Delta U$ is the change in internal energy

Q is the heat absorbed by the system

W is the work done by the system

in this problem, Q=1000 J and W=500 J, so we have

$\Delta U=1000 J-500 J=500 J$

Since the initial internal energy is $U_i = 2000 J$, we the final energy is given by:

$\Delta U=U_f -U_i\\U_f = U_i + \Delta U=2000 J+500 J=2500 J$