The frame is being enlarged to hang on a gallery wall. Using the scale factor of 1 in = 3 ft, give the new dimensions of the outside edges of the frame. New Dimensions: 5in. = ___________ 7in=___________

Answer:
Part A) [tex]5\ in=15\ ft[/tex]
Part B) [tex]7\ in=21\ ft[/tex]
Step-by-step explanation:
we know that
The scale factor is [tex]\frac{1}{3}\frac{in}{ft}[/tex]
so
using proportion
Part A)
[tex]\frac{1}{3}\frac{in}{ft}=\frac{5}{x}\frac{in}{ft}\\ \\x=5*3\\ \\x=15\ ft[/tex]
therefore
[tex]5\ in=15\ ft[/tex]
Part B)
[tex]\frac{1}{3}\frac{in}{ft}=\frac{7}{x}\frac{in}{ft}\\ \\x=7*3\\ \\x=21\ ft[/tex]
therefore
[tex]7\ in=21\ ft[/tex]