Answer:
D) a reflection over the line x = 0 followed by a reflection over the line y = 0.
Step-by-step explanation:
In this problem, the original figure is in quadrant I (1) and the second image is in quadrant III (3). In order for the figure to make this transition and be 'flipped' into the opposite direction of the original figure, a reflection would have to take place. If triangle 'A' is reflected over the line y = x or y = -x, the orientation of the triangle would stay the same, meaning the point of the triangle would still face upward. If you reflect over the line x = 0 and then again over the line x = 0 (as in C), your triangle would be in the same spot. However, if you reflect triangle 'A' over x = 0, you would get a 'flipped image' into quadrant 4 and the orientation of the triangle would face downward. Following this reflection by another reflection over the line y=0 would give you the mirror image in quadrant III (3). So, D is the correct sequence of reflections.
