Question

Infrared radiation _____. has wavelengths that are shorter than visible light is part of the visible light spectrum has wavelengths that are longer than visible light has the same wavelengths as ultraviolet radiation

Answer 1

Answer: has wavelengths that are longer than visible light

Explanation: Electromagnetic spectra comprises of different electromagnetic waves which are arranged in order of increasing wavelengths or decreasing energies.

In order from highest to lowest energy, the waves are arranged as: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

$E=\frac{hc}{\lambda}$

E= energy

h= planck's constant

c= velocity of light

$\lambda$ = wavelength

As wavelength and energy are inversely related, the wave having higher wavelengths will be lowest in energy. Thus as infrared radiation have lower energy as compared to visible radiation. Thus  infrared radiation have higher wavelength as compared to visible radiation.

Answer 2

Answer: has wavelengths that are longer than visible light

Explanation: Electromagnetic spectra comprises of different electromagnetic waves which are arranged in order of increasing wavelengths or decreasing energies.

In order from highest to lowest energy, the waves are arranged as: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

E= energy

h= planck's constant

c= velocity of light

= wavelength

As wavelength and energy are inversely related, the wave having higher wavelengths will be lowest in energy. Thus as infrared radiation have lower energy as compared to visible radiation. Thus  infrared radiation have higher wavelength as compared to visible radiation.