Question

The molality of calcium chloride (CaCl2) in an aqueous solution is 2.46 m. What is mole fraction of the solute?

Answer 1

Given that CaCl2 = 2.46 m

Therefore 2.46 mole of CaCl2 present in 1.00 g of solution

Mass of 2.46 mole CaCl2= number of mole * molar mass

= 2.46 mole  * 110.98 g/mol

= 273.01 g

Mass of water or solvent = mass of solution – mass of solute  

= 1000 g -273.01 g

= 726.99 g

Mole of water = amount in g / molar mass

= 726.99 g/18.02 g/ mole

= 40.34 moles

Mole fraction of CaCl2 = number of mole of CaCl2 / total moles

= 2.46 /2.46+40.34

= 2.46/42.8

= 0.057  

Answer 2

The mole fraction of the solute, CaCl₂ is 0.042

How to determine the mole solute, CaCl₂

• Molality = 2.46 m
• Mass of water = 1 kg
• Mole of CaCl₂ =?

Mole = Molality × mass of water

Mole of CaCl₂ = 2.46 × 1

Mole of CaCl₂ = 2.46 moles

How to determine the mole of water

• Mass of water = 1 Kg = 1000 g
• Molar mass of water = 18 g/mol
• Mole of water =?

Mole = mass / molar mass

Mole of water = 1000 / 18

Mole of water = 55.56 moles

How to determine the mole fraction of CaCl₂

• Mole of CaCl₂ = 2.46 moles
• Mole of water = 55.56 moles
• Total mole = 2.46 + 55.56 = 58.02 mole
• Mole fraction of CaCl₂ =?

Mole fraction = mole of solute / total mole

Mole fraction of CaCl₂ = 2.46 / 58.02

Mole fraction of CaCl₂ = 0.042

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