Respuesta :
For this case we must determine the inverse of the following function:
[tex]f (x) = 3x-2[/tex]
Step 1:
We write [tex]y = f (x)[/tex]
[tex]y = 3x-2[/tex]
Step 2:
We clear x:
[tex]y + 2 = 3x\\\frac {y + 2} {3} = x[/tex]
Step 3:
"x" and "y" are exchanged:
[tex]y = \frac {x + 2} {3}[/tex]
The inverse is:
[tex]f ^ {- 1} (x) = \frac {x + 2} {3}[/tex]
ANswer:
[tex]f ^ {- 1} (x) = \frac {x + 2} {3}[/tex]
The inverse of a function is the opposite of the function.
The inverse of the function is: [tex]\mathbf{f^{-1}(x) =\frac{ x + 2}{3}}[/tex]
The function is given as:
[tex]\mathbf{f(x) = 3x - 2}[/tex]
Express as:
[tex]\mathbf{y = 3x - 2}[/tex]
Swap x and y
[tex]\mathbf{x = 3y - 2}[/tex]
Add 2 to both sides
[tex]\mathbf{3y = x + 2}[/tex]
Divide both sides by 3
[tex]\mathbf{y =\frac{ x + 2}{3}}[/tex]
Rewrite as:
[tex]\mathbf{f^{-1}(x) =\frac{ x + 2}{3}}[/tex]
Hence, the inverse of the function is: [tex]\mathbf{f^{-1}(x) =\frac{ x + 2}{3}}[/tex]
Read more about inverse functions at:
https://brainly.com/question/10300045