Answer:
Given the function: [tex]f(x) = \frac{x+2}{3x-4}[/tex]
Step 1: Replace f(x) by y;
[tex]y= \frac{x+2}{3x-4}[/tex]
Step 2: Interchange the variables x and y.
[tex]x= \frac{y+2}{3y-4}[/tex]
Step 3: Solve for y in terms of x;
[tex]x(3y-4) = y+2[/tex]
Using distributive property: [tex]a\cdot (b+c) = a\cdot b+ a\cdot c[/tex]
[tex]3xy-4x = y+2[/tex]
Add 4x to both sides we get;
[tex]3xy= y+2+4x[/tex]
[tex]3xy-y=2+4x[/tex]
[tex]y(3x-1)=2+4x[/tex]
⇒[tex]y = \frac{4x+2}{3x-1}[/tex]
Step 4: Replace y with [tex]f^{-1}(x)[/tex]
[tex]f^{-1}(x) = \frac{4x+2}{3x-1}[/tex]
Therefore, the inverse operation of a given function is:
[tex]f^{-1}(x) = \frac{4x+2}{3x-1}[/tex]