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Construct the graph of the equation y=kx if it is known that the point B belongs to the graph. The graph of which of these two equations goes through point M(−10, 15)?

1. B(2, −3)

2. B(3 1/3, −2)

Respuesta :

Answer:

None of the graphs of the equations pass through M(−10, 15).

Step-by-step explanation:

We are given the function [tex]y=kx[/tex].

It is given that the point B lies on the graph of the given function.

1. B(2, −3)

That is, x= 2 and y= -3

So, y= kx ⇒ -3 = 2k ⇒ [tex]k=\frac{-2}{3}[/tex]

Thus, the function is [tex]y=\frac{-2x}{3}[/tex]

2. [tex]B(3\frac{1}{3},-2)[/tex] i.e. [tex]B(\frac{10}{3},-2)[/tex]

That is, [tex]x= \frac{10}{3}[/tex] and y= -2

So, y= kx ⇒ [tex]-2 = \frac{10k}{3}[/tex] ⇒ [tex]k=\frac{-6}{10}[/tex] ⇒ [tex]k=\frac{-3}{5}[/tex]

Thus, the function is [tex]y=\frac{-3x}{5}[/tex]

From the graph plotted below, we get that,

None of the graphs of the equations pass through M(−10, 15).

Ver imagen wagonbelleville

Answer:

None will go through.

Step-by-step explanation:

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