Answer:
GE=10
FJ=5
Step-by-step explanation:
We know that in a traingle
[tex]a^{2}+b^{2} =c^{2}[/tex]
a=HE=6
b=FE=8
Once we enter it into the equation, we find that we get
36+64=100
The square root of 100=10
GE=HF so HE=10.
Half of HE(10) is FJ(5)
Hope this help :)
