1kg of water needs to recieve 4200J of energy to go from 90 degrees to 91 degrees.
What is the specific heat capacity of water? What are the units?

Respuesta :

For the change in temperature of water we require heat which is given by formula

[tex]Q = m s \Delta T[/tex]

here we will have

[tex]Q = 4200 J[/tex]

[tex]m = 1 kg[/tex]

initial temperature = 90 degree C

final temperature = 91 degree C

now we will have

[tex]\Delta T = 91 - 90 = 1 degree C[/tex]

from above equation we will have

[tex]4200 J = (1 kg) s (91 - 90)^0C[/tex]

now we will have

[tex]s = frac{4200 J}{(1 kg)(1 ^0C)[/tex]

[tex]s = 4200 J/(kg ^0C)[/tex]

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