Question

PLEASE HELP URGENT

in guinea pigs, black fur (B) is dominant over white fur (b). Cross a heterozygous (hybrid) black guinea pig with a homozygous (purebred) white guinea pig. Complete a Punnett square, identify the genotype(s), phenotype(s), and probability (% and fraction) that the offspring will be black and white?

Answer 1

I took a picture of the answer! ^

Answer 2

In this case, the genotype of the parent gene, and probability of the gene are:

The genotype - Bb (heterozygous black), bb (hozygous white)

Probability of (% and fraction) of white and black - 2/4 or 50%

• The heterozygous (hybrid) black guinea pig = Bb
• Hozygous (purebred) white guinea pig = bb
• When these two are crossed the resulting genotypes are

cross: Bb x bb

   B      b

b   Bb    bb

b  Bb    bb

Offsprings would be= Bb, Bb, bb, bb

where Bb = black & white phenotype

and bb= white phenotype

So, Probability of (% and fraction) of white and black - 2/4 or 50%

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