can you help me with my math questions

Answer:
Question 4. (x-5)² and (4c-3)(4c+3)
Question 5. Expressions for the areas are 8(7x-1)(x-2) and -8(7x-1)(x-2).
Question 6. Buyer is not right as the values of x are not same.
Step-by-step explanation:
Question 4). x²- 10x+25 = x²-2×5x+5²
= (x-5)² since (a-b)² = a²+b²-2ab
16c²-9 = (4c)²- 3²
= (4c-3)(4c+3) Since a²-b²=(a-b)(a+b)
Question 5). Area of one square painting = 81x²-90x+25 =(9x-5)²
Area of second square painting = 25x²+30x+9 =(5x+3)²
Now the difference between the areas of these two paintings
= 81x²-90x+25-(25x²+30x+9) = (9x-5)²-(5x+3)²
= (9x-5+5x+3)(9x-5-5x-3) = (14x-2)(4x-8) = 8(7x-1)(x-2)
Since we have to calculate the difference of the areas of two paintings then it may also be written as 25x²+30x+9-(81x²-90x+25)= -8(7x-1)(x-2)
Question.6 The areas are given as 1600 in² and 484 in² then
(9x-5)²= 1600 ⇒ (9x-5) =√1600
9x-5 =40 ⇒ 9x = 40+5 =45
Or x=45/9 =5
and for other painting (5x+3)²=484
5x+3=√484 = 22
5x =22-3
5x =19 ⇒ x=19/5
So the values of x are not same. So buyer is not right.
Answer:
4 part 1: Error was in the second step (2(x)(5)
part 2: Error was in the second step (4c)² - 3³ ≠ (4c - 3)²
5. part 1: 56x² + 60x + 16
part 2: The values of x in the 2 expressions are not the same.
Step-by-step explanation:
Question 4 part 1
x² - 10x + 25
the factors are -5 and -5
x² - 5x - 5x + 25 = x(x-5) - 5(x-5)
foctoring out (x-5)
= (x-5)(x-5) = (x - 5)²
Question 4 part 2
16c² - 9 = (4c)² - 3²
This is a different of 2 squares
(4c)² - 3² = (4c - 3)(4c + 3)
question 5
part 1
Subtracting the two quadratic expressions
81x² + 90x + 25 - (25x² + 30x + 9)
= 81x² + 90x + 25 - 25x² - 30x - 9
= 56x² + 60x + 16
part 2 solving for x
81x² + 90x + 25 = 1600
81x² + 90x = 1600-25
9x² + 10x = 175
x² + 1.111x + 0.556² = 175 + 0.3086
(x + 0.556)² = 175.3086
x = ±13.2404 - 0.556
= 12.6844 or -13.7964
25x² + 30x + 9 = 484
25x² + 30x = 484 - 9
x² + 1.2x + 0.6² = 19+0.36
(x + 0.6)² = 19.36
x = ±4.4 - 0.6
= 3.8 or -5