Which system of inequalities represents region Z?

Answer:
The system of inequalities is
[tex]y\geq 3x-2[/tex]
[tex]y<-(1/5)x+2[/tex]
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
[tex]A(0,-2), B(1,1)[/tex]
Find the slope of AB
[tex]m=(1+2)/(1-0)=3[/tex]
The equation of the line into slope intercept form is equal to
[tex]y=mx+b[/tex]
we have
[tex]m=3[/tex]
[tex]b=-2[/tex] ----> the point A is the y-intercept
substitute
[tex]y=3x-2[/tex] -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
[tex]y\geq 3x-2[/tex]
step 2
Find the equation of the dashed red line
Let
[tex]C(0,2), D(5,1)[/tex]
Find the slope of CD
[tex]m=(1-2)/(5-0)=-1/5[/tex]
The equation of the line into slope intercept form is equal to
[tex]y=mx+b[/tex]
we have
[tex]m=-1/5[/tex]
[tex]b=2[/tex] ----> the point C is the y-intercept
substitute
[tex]y=-(1/5)x+2[/tex] -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
[tex]y<-(1/5)x+2[/tex]
The system of inequalities is
[tex]y\geq 3x-2[/tex]
[tex]y<-(1/5)x+2[/tex]