Question

(−8y 2 −9y)−(−8y 3 +9y 2 −5y) solve in standard form

Answer 1

Answer:

(−8y^2 −9y)−(−8y^3 +9y^2 − 5y)

= −8y^2 − 9y + 8y^3 - 9y^2 + 5y

= 8y^3 - 17y^2 - 4y

Answer 2

The standard of the polynomial is $\rm 8y^3-y^2-4y$.

Given

Polynomial; $\rm (-8y^ 2 -9y)-(-8y ^3 +9y ^2 -5y)$.

The standard form of the polynomial;

A polynomial is said to be in standard form when the terms in an expression are arranged from the highest degree to the lowest degree.

We have to simplify the polynomial then arrange the polynomial from the highest degree to the lowest degree.

Therefore,

The standard form of the polynomial is given by;

$\rm =(-8y^ 2 -9y)-(-8y ^3 +9y ^2 -5y)\\\\\rm =-8y^ 2 -9y+8y ^3 -9y ^2 +5y\\\\=8y^3-9y^2+8y^2-9y+5y\\\\= 8y^3-y^2-4y$

Hence, the standard of the polynomial is $\rm 8y^3-y^2-4y$.

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