Question

An electron in an x-ray machine is accelerated through a potential difference of 1.00 × 104 v before it hits the target. What is the kinetic energy of the electron in electron volts?

Answer 1

Kinetic energy of electron is gained by the potential energy that it is getting through the potential applied across it

now here we know that that

$V = 1.00 \times 10^4 Volts$

charge that is accelerated is an electron

so we will have

$U = qV$

here we know that

$q = 1e$

$U = (e)(1.00 \times 10^4 V)$

$U = 1.00 \times 10^4 eV$

so kinetic energy will be same as potential energy which is equal to

$KE = 1.00 \times 10^4 eV$

Answer 2

The kinetic energy to move the electron is 1*10^4eV

Data;

• Potential Difference = 1.0*10^4V
• number of electrons = 1

Kinetic Energy

This is the energy required to accelerate the electron from one point to another.

$K.E = 1.0*10^4(1e) = 1*10^4eV$

The kinetic energy to move the electron is 1*10^4eV

Learn more on kinetic energy here;

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