Question

which would prove that ABC ~ XYZ? check all that apply

Answer 1

Answer:

Option: A and C are correct.

Step-by-step explanation:

For ΔABC~ΔXYZ.

option: A

$\dfrac{BA}{YX}=\dfrac{BC}{YZ}=\dfrac{AC}{XZ}$

if this property is satisfied than the SSS similarity theorem will hold and the two triangles will be similar.

( since  Side-Side-Side (SSS) Similarity Theorem - If the lengths of the

corresponding sides of two triangles are proportional, then the

triangles must be similar )

Option: C

$\dfrac{AC}{XZ}=\dfrac{BA}{YX}$ and ∠A≅∠X.

in this case the SAS similarity will hold true and

hence ΔABC~ΔXYZ.

( since Side-Angle-Side (SAS) Similarity Theorem - If an angle of one

triangle is congruent to an angle of a second triangle and the lengths of

the sides including these angles are proportional, then the triangles

must be similar ).

Answer 2

Answer: A and C

Step-by-step explanation:

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