Question

the length of a rectangle is 3 inches greater than the width. write a polynomial that represents the area of the rectangle

Answer 1

Answer:

Length of a rectangle is 3 inches greater than the width, so:

L = W + 3

Area of a rectangle:

A = L x W

A = ( W + 3 ) x W

A = W2 + 3 W ----------------- Polynomial representing area of the rectangle in terms of Width.

Substitute W = 4 to find the area of the rectangle.

A = 42 + 3 (4)

A = 16 + 12

A = 28 inch2

L = W + 3

L = 4 + 3

L = 7 inches

Answer 2

The polynomial that represents the area of the rectangle is $\rm W^2+3W$.

Given

The length of a rectangle is 3 inches greater than the width.

Area of the rectangle;

The area of the rectangle is given by the product of the length and width.

The area of the rectangle is given by;

$\rm Are \ of \ the \ rectangle=Length \times width$

Let, the length of the rectangle be L and the width of the rectangle is W.

The length of a rectangle is 3 inches greater than the width.

L = W + 3

Therefore,

The polynomial that represents the area of the rectangle is;

$\rm Are \ of \ the \ rectangle=Length \times width\\\\\rm Are \ of \ the \ rectangle=W \times (W+3)\\\\\rm Are \ of \ the \ rectangle=W^2+3W$

Hence, the polynomial that represents the area of the rectangle is $\rm W^2+3W$.

To know more about the area of the rectangle click the link given below.

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