The correct answer is 400 KJ/mol.
The given reaction:
NO₂ (g) + CO₂ (g) ⇒ NO (g) + CO₂ (g)
The activation energy or Ea for the reaction is 300 KJ/mol.
The change in enthalpy for the reaction is, ΔH = -100 KJ/mol, this is for forward reaction, for backward or reverse reaction, ΔH = 100 KJ/mol
The Ea for reverse reaction is calculated by using the formula,
Ea (forward) + ΔH
= 300 + (+100)
= 400 KJ/mol
Therefore, the activation energy for the reverse reaction is 400 KJ/mol