Question

The width of a rectangle is 6 inches less than the length The perimeter is 44 inches Find the length and the width.

Answer 1

Answer:

$l=14\:in.,w=8\:in.$

Step-by-step explanation:

Let the length of the rectangle be $l\:in.$ and the width be $w\:in.$.

Then

$w=l-6...(1)$

The perimeter is given by

$P=2w+2l...(2)$

We put equation (1) into equation (2) to get;

$\Rightarrow 44=2(l-6)+2l$

We can expand the bracket here. But let us divide through by 2 first to get;

$\Rightarrow 22=(l-6)+l$

Group like terms to get;

$\Rightarrow 22=l-6+l$

$\Rightarrow 22+6=l+l$

$\Rightarrow 28=2l$

Divide by 2 again;

$\Rightarrow 14=l$

The length is 14 inches.

$w=14-6=8$

The width is 8 inches.

Answer 2

Answer:

Length is 14 inches. Width is 8 inches.

Step-by-step explanation:

Let the length of rectangle is l.

Let the width of rectangle is w.

From question statement,we observe that

The width of a rectangle is 6 inches less than the length.

w= l-6

P = 2l+2w = 44 inches

2l + 2( l-6) = 44

2l+2l-12 = 44

4l-12 = 44

4l = 44+12

4l = 56

Dividing by 4

l = 56/4

l = 14 inches

Hence, the width is

w = 14-6 = 8 inches

Hence, the length of rectangle is 14 inches and the width is 8 inches.