Question

The resistance (R) in a wire increases when the length of the wire (L) increases. Write the correct equation for this scenario, and solve for when the length is 1. Length Resistance 10 2 15 3
a. R = 20 over L; R = 20
b. R = .2L; R = 5
c. R = .2L; R = .2
d. R = 20 over L; R = 5

Answer 1

Answer: c. R = 0.2L ; R =0 .2

Step-by-step explanation:

Given: When length of wire is $L_1=$ 10 units, then resistance of wire $R_1=$=2 ohm

When length of wire is $L_2=$15 units, then resistance of wire $R_2=$=3 ohm

Since, the resistance (R) in a wire increases when the length of the wire (L) increases. Therefore, they are directly proportional.

$\frac{R}{L}=\frac{R_1}{L_1}$

$\frac{R}{L}=\frac{2}{10}\\\Rightarrow\ R=0.2L$

Now, for Length L=1 unit, we have

$R=0.2(1)=0.2$