write the equation of a line that is perpendicular to the given line and that passes through the given point.
y + 2 = 1/3(x-5) ; (-4, 3)

write the equation of a line that is perpendicular to the given line and that passes through the given pointy 2 13x5 4 3 class=

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Answer:

The equation would be y = -3x - 9

Step-by-step explanation:

Since we have the slope of 1/3, we know the slope of a perpendicular line would be -3. This is because perpendicular lines have opposite and reciprocal slopes. We can then use this and the point to solve in point-slope form.

y - y1 = m(x - x1)

y - 3 = -3(x + 4)

y - 3 = -3x - 12

y = -3x - 9

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