Answer: [tex]2x+y-110=0[/tex]
Step-by-step explanation:
Given: A line is drawn through (twenty, seventy) and (twenty-five, sixty).
The points through which line is passing are (20,70) and (25,60)
The slope of the line= [tex]\frac{y_2-y_1}{x_2-x_1}=\frac{60-70}{25-20}=\frac{-10}{5}=-2[/tex]
The equation of line with slope m and passing through point [tex](x_0,y_0)[/tex] is [tex](y-y_0)=m(x-x_0)[/tex]
Therefore, the equation of the trend line with slope -2 and point (20,70) will be
[tex](y-70)=-2(x-20)\\\Rightarrow\ y-70=-2x+40\\\Rightarrow\ 2x+y-70-40\\\Rightarrow2x+y-110=0[/tex]