[tex]4 + \frac{3}{7}x - 2 - \frac{2}{7}x\\\\\text{combine like terms}\\\\\left(\dfrac{3}{7}x-\dfrac{2}{7}x\right)+(4-2)=\dfrac{3-2}{7}x+2=\boxed{\dfrac{1}{7}x+2}[/tex]
Answer:
The correct answer to this problem is: 2 + 1/7x
