Question

PLEASE HELP
A boat is 20 ft away from a point perpendicular to the shoreline. A person stands at a point down the shoreline so that a 60° angle is formed between the closest point to the boat, the person, and the boat. How far is the person from the boat? Draw a picture showing the right triangle. Round your answer to the nearest tenth of a
foot. Show your work.

Answer 1

Answer:

Step-by-step explanation:

Since it is given that Distance between a boat that is away from a point perpendicular to the shore line = 20 feet

Angle of elevation that is formed between the closest point to the boat and the person = 60°

Now, we need to find the distance between the person and the boat.

Using the trigonometric ratios,

$sin60^{{\circ}}=\frac{AB}{AC}$

$\frac{\sqrt{3}}{2}=\frac{20}{H}$

$\frac{40}{\sqrt{3}}=H$

$H=\frac{40}{1.7}$

$H=23.0 feet$

Thus, the distance between the person and the boat is 23 feet.