Question

Write the equation of a line in slope -intercept form that is perpendicular to the given line and passes through the point 9,-32

Answer 1

Answer:

$y=-\frac{7}{2}x-\frac{1}{2}$

Step-by-step explanation:

The line Y=2/7x-1/7 in the comments has slope 2/7. A perpendicular line will have the negative reciprocal of 2/7. It's -7/2.

To write the equation, substitute -7/2 and the point (9,-32) into

$y-y_1 = m(x-x_1)$

$y--32=-\frac{7}{2}(x-9)\\\\y+32=-\frac{7}{2}x +\frac{7*9}{2}\\\\y+32=-\frac{7}{2}x+\frac{63}{2}\\\\y=-\frac{7}{2}x+\frac{63-64}{2}\\\\y=-\frac{7}{2}x-\frac{1}{2}$