Determine the currents given in the picture.

Answer:
The value of currents are [tex]I_1=0A[/tex], [tex]I_2=1A[/tex] and [tex]I_3=1A[/tex].
Step-by-step explanation:
The Ohm's law states that
[tex]V=IR[/tex]
It is given that the V₁=3V and V₂=4V.
In a parallel circuit:
[tex]I_2=I_1+I_3[/tex] .... (1)
Equation for first loop is,
[tex]V_1=4I_1+3I_2[/tex]
[tex]3=4I_1+3I_2[/tex] ..... (2)
Equation for second loop is,
[tex]V_2=1I_3+3I_2[/tex]
[tex]4=1I_3+3I_2[/tex] ..... (3)
On solving (1), (2) and (3) we get
[tex]I_1=0[/tex]
[tex]I_2=1[/tex]
[tex]I_3=1[/tex]
Therefore the value of currents are [tex]I_1=0A[/tex], [tex]I_2=1A[/tex] and [tex]I_3=1A[/tex].