Question

Mustafa, Heloise, and Gia have written more than a combined total of 2222 22 articles for the school newspaper. Heloise has written 14\dfrac{1}{4} 4 1 ? as many articles as Mustafa has. Gia has written 32\dfrac{3}{2} 2 3 ? as many articles as Mustafa has. Write an inequality to determine the number of articles, mm m , Mustafa could have written for the school newspaper.

Answer 1

Answer: $m>8$

Mustafa could have written more than 8 articles for the newspaper.

Step-by-step explanation:

Given: Heloise has written 1/4 as many articles as Mustafa has. Gia has written 3/2 as many articles as Mustafa has.

Let m be the number of articles Mustafa writes.

Then articles written by Heloise=$\frac{1}{4}m$

And articles written by Gia=$\frac{3}{2}m$

The total number of articles =$m+\frac{1}{4}m+\frac{3}{2}m=\frac{4m+m+6m}{4}=\frac{11m}{4}$

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

$\frac{11m}{4}>22\\\Rightarrow\ m>\frac{22\times4}{11}\\\Rightarrow\ m>8$

Hence, Mustafa could have written more than 8 articles for the newspaper.

Answer 2

Answer:

M>8 and the equation is m+  41 m+23  m>22

Step-by-step explanation:

Mustafa has written more than 888 articles.

Hint #33 / 3

The inequality is:

m+\dfrac{1}{4}m+\dfrac{3}{2}m>22m+  

4 1m+23 m>22m, plus, start fraction, 1, divided by, 4, end fraction, m, plus, start fraction, 3, divided by, 2, end fraction, m, is greater than, 22

The solution set is m>8m>8m, is greater than, 8.