Question

A church luncheon made $842. Adult tickets cost $10 each and children's tickets cost $6 each. The number of children was 12 more than twice the number of Adults. how many of each ticket were sold?

Answer 1

Answer:

42 adults and 96 children

Step-by-step explanation:

42x + 96c = 842

x=10

c=6

Answer 2

Answer:

adult tickets 35 and children's ticket 82

Step-by-step explanation:

Given: A church luncheon made $\ 842$. Adult tickets cost $\ 10$ each and children's tickets cost  $\ 6$ each. The number of children was $12$ more than twice the number of Adults.

To Find: how many of each ticket were sold.

Solution:

Let the number of adults be $=\text{a}$

Let the number of children be $=\text{c}$

cost of adult ticket       $=\ 10$

cost of children ticket  $=\ 6$

Total value of tickets sold $=\ 842$

Now,

total sale of ticket

                            $=10\text{a}+6\text{c}$

as given

    $\text{c}=2\text{a}+12$

putting in equation

                      $842=6(12+2\text{a})+10\text{a}$

                      $842=22\text{a}+72$

                      $770=22\text{a}$

                      $\text{a}=35$

now,

    $\text{c}=2\text{a}+12$

    $\text{c}=2\times35+12$

    $\text{c}=82$

Hence number of adult tickets are $35$ and number of children's ticket are $82$.