Solve...........................

Answer:
Right option is B. x = -3 ± 2√5
Step-by-step explanation:
Given equation,
x² + 6x - 11 = 0
Using quadratic formula,
[tex]x = \frac{-b ± \sqrt{b^{2} -4ac}}{2a}[/tex]
Comparing from general quadratic equation: ax² + bx + c = 0
Here, a= 1 b = 6 and c = -11
so,
[tex]x = \frac{-6 ± \sqrt{6^{2} -4·1·(-11)}}{2·1}[/tex]
[tex]x = \frac{-6 ± \sqrt{36 +44}}{2}[/tex]
[tex]x = \frac{-6 ± \sqrt{80}}{2}[/tex]
x = -3 ± 2√5
Hence right option is B. x = -3 ± 2√5