Respuesta :

Answer:

Right option is B. x = -3 ± 2√5

Step-by-step explanation:

Given equation,

x² + 6x - 11 = 0

Using quadratic formula,

[tex]x = \frac{-b ± \sqrt{b^{2} -4ac}}{2a}[/tex]

Comparing from general quadratic equation: ax² + bx + c = 0

Here, a= 1 b = 6 and c = -11

so,

[tex]x = \frac{-6 ± \sqrt{6^{2} -4·1·(-11)}}{2·1}[/tex]

[tex]x = \frac{-6 ± \sqrt{36 +44}}{2}[/tex]

[tex]x = \frac{-6 ± \sqrt{80}}{2}[/tex]

x = -3 ± 2√5

Hence right option is B. x = -3 ± 2√5


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