Respuesta :
Answer:
A rectangular lot with dimensions 72.2 feet long and 50 feet wide is given.
1. We need to find the AREA of the rectangular lot in order to find the size of the park.
As, Area of a rectangle = Length × Width
i.e. Area of the lot = 72.2 × 50
i.e. Area of the lot = 3610 feet²
Hence, the size of the park is 3610 feet².
2. We need to find the PERIMETER of the rectangular lot in order to find the amount of fencing needed.
As, Perimeter of rectangle = 2 × ( Length + Width )
i.e. Perimeter of the lot = 2 × ( 72.2 + 50 )
i.e. Perimeter of the lot = 2 × 122.2
i.e. Perimeter of the lot = 244.4 feet.
Hence, the amount of fencing needed for the park of the park is 244.4 feet.
Given information
The length of the lot is 72.2 feet.
The width of the lot is 50 feet.
- 1) Size of the park-
Size of the rectangle park is equal to the area of the park.
Area of rectangle
Area of rectangle is the product of the length and the width.
Thus the area of the rectangle park is,
[tex]A=72.2\times 50\\ A=3610[/tex]
Thus the size of the rectangle park is 3610 squared feet.
- 2) Fencing around the park-
Fencing around the park is equal to the perimeter of the rectangular park.
Perimeter of rectangle
The perimeter of the rectangle is twice the sum of the length and width.
Thus the perimeter of the rectangular park is,
[tex]P=2(72.2+50)\\ P=2\times 122.2\\ P=244.4[/tex]
Thus the fencing around the park is equal to the 244.4 feet.
Hence the size of the rectangle park is 3610 squared feet and the fencing around the park is equal to the 244.4 feet.
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