a weight hangs from a rope 20 feet long. It swings through an angle of 27 degrees each second. how far does the weight travel each second? round to the nearest 0.1 foot

Respuesta :

Answer:

S=9.42 feet

Step-by-step explanation:

Since, the length of the rope is 20 feet and it swings through an angle of 27° each second, let s be the distance traveled by the weight, then

using the formula, S=[tex]\frac{{\theta}}{360^{{\circ}}}{\times}2{\pi}r[/tex]

Placing the given values, we get

S=[tex]\frac{27^{{\circ}}}{360^{{\circ}}}{\times}2{\times}\frac{22}{7}{\times}20[/tex]

=[tex]0.075{\times}\frac{44}{7}{\times}20[/tex]

=[tex]9.42 feet[/tex]


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