Answer:
The length of AD is [tex]\sqrt{13}\ units[/tex]
Step-by-step explanation:
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex]A(2,4)\\B(0,1)[/tex]
substitute the values
[tex]d=\sqrt{(1-4)^{2}+(0-2)^{2}}[/tex]
[tex]d=\sqrt{(-3)^{2}+(-2)^{2}}[/tex]
[tex]dAD=\sqrt{13}\ units[/tex]
