Answer:
Probability that the spinner will stop on an odd number or a multiple of 5 is 0.6
Step-by-step explanation:
Probability = [tex]\frac{Required outcomes}{Total possible outcomes}[/tex]
We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20
Total possible outcomes: 20
Outcomes that spinner will stop on an odd number, n(Odd): 10
1, 3, 5, 7, 9, 11, 13, 15, 17, 19
Probability of spinner stoping on Odd number:
P(Odd) = [tex]\frac{n(Odd)}{Total}[/tex] = [tex]\frac{10}{20}[/tex] = [tex]\frac{1}{2}[/tex] = 0.5
Outcomes that spinner will stop on a multiple of 5, n(5): 4
5, 10, 15, 20
Probability of spinner stoping on multiple of 5:
P(5) = [tex]\frac{n(5)}{Total}[/tex] = [tex]\frac{4}{20}[/tex] = [tex]\frac{1}{5}[/tex] = 0.2
Odd numbers which are a multiple of 5 are: 5 and 15
So,
P(Odd and 5) = [tex]\frac{2}{20}=\frac{1}{10}=0.1[/tex]
Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:
P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6
