Question

If the solubility of a gas in water is 1.22 g/L at 2.75 atm, what is its solubility (in g/L) at 1.0 atm?

Answer 1

Answer:

0.44 g/L.

Explanation:

• This problem is an application on Henry's law.

• Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.

• Solubility of the gas ∝ partial pressure

• If we have different solubility at different pressures, we can express Henry's law as:

• S₁/P₁ = S₂/P₂,

• S₁ = 1.22 g/L and P₁ = 2.75 atm

• S₂ = ??? g/L and P₂ = 1.0 atm

• So, The solubility of the gas at 1.0 atm (S₂) = S₁.P₂/P₁ = (1.22 g/L x 1.0 atm) / (2.75 atm) = 0.44 g/L.