Answer:- Third choice is correct, 17.6 moles
Solution:- The given balanced equation is:
[tex]Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4[/tex]
We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.
From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.
It is a simple mole to mole conversion problem. We solve it using dimensional set up as:
[tex]2.94molAl_2(SO_4)_3(\frac{6molKOH}{1molAl_2(SO_4)_3})[/tex]
= 17.6 mol KOH
So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.
