Question

Find the equation of the axis of symmetry for the parabola y=x^2-6x+41/5

Answer 1

Answer:

x = 3

Step-by-step explanation:

given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the equation of the axis of symmetry is

x = - $\frac{b}{2a}$

y = x² - 6x + $\frac{41}{5}$ is in standard form

with a = 1 and b = - 6, hence

x = - $\frac{-6}{2}$ = 3

equation of axis of symmetry is x = 3