Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
Solution : Given,
Solubility of a gas in water = 1.22 g/L (at 2.75 atm pressure)
At pressure = 1 atm, Solubility of a gas = ?
Now we have to calculate the solubility of a gas.
At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L
At 1 atm pressure, the solubility of a gas in water = [tex]\frac{1atm}{2.75atm}\times 1.22g/L=0.4436g/L[/tex]
Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
