Explanation:
Molarity is defined as number of moles per liter of solution.
Mathematically, molarity = [tex]\frac{no. of moles}{Volume (in L) of solution}[/tex]
It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.
molarity = [tex]\frac{no. of moles}{Volume of solution in liter}[/tex]
0.0800 M = [tex]\frac{no. of moles}{0.05 L}[/tex]
no. of moles = 1.6 mol
Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.
No. of moles = [tex]\frac{mass in grams}{molar mass}[/tex]
mass in grams = [tex]no. of moles \times molar mass of CuSO_{4}.5H_{2}O[/tex]
= [tex]1.6 mol \times 249.68 g/mol[/tex]
= 399.488 g
Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.
