Question 1:
The answer is 256 feet
It states that:
[tex]h(t) = 400 - 16t^2[/tex]
To find h(3), we can substitute the variable t with 3:
[tex]h(3) = 400-16\times3^2\\h(3) = 256[/tex]
Question 2:
The answer is 144 feet
To find the height it traveled, you can subtract the height of the bundle before the drop by the height above the ground after 3 seconds:
[tex]400 - 256 = 144[/tex]
Question 3:
The answer is 48 feet per seconds
The formula for speed is:
[tex]speed = \frac{distance}{time}[/tex]
So to calculate the speed, we substitute the distance with the answer from question two and time with 3.
[tex]speed = \frac{144}{3}\\speed = 48[/tex]
I felt like I rushed this answer. If somethings doesn't make sense, feel free to ask in the comments.
