Question

A big box of sausages (30 kg) are lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant speed, a distance of 1.75 m, what work is done by gravity?

Answer 1

Answer:

The work done by gravity moving the box up is -514.5 Joules.

Explanation:

The gravity acts in the direction of the displacement, which in this case is negative (ground - top shelf), and so the resulting work is negative. The work is calculated as:

$W_g = mg\Delta h = 30kg\cdot 9.8\frac{m}{s^2}\cdot(0-1.75)m=-514.5J$

The work done by gravity moving the box up is -514.5 Joules.

Answer 2

Work done by gravity depends upon the mass and height of the object. The work done by the gravity on the 30 kg sausage is 514.5 J.

Gravitational work:

$Wg = mg h$

Where,

$m$ - mass of sausage = 30 kg

$g$- gravitational acceleration = 9.8 m/s²

$h$ - height = 1.75 m

Put the values in the formula,

$Wg = 30 \times 9.8 \times 1.75 \\\\Wg = 514.5\rm \ J$

Therefore, the work done by the gravity on the 30 kg sausage is 514.5 J.

Learn more about gravity:

https://brainly.com/question/8154365