[tex]\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill&1178.29\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years\dotfill &1 \end{cases} \\\\\\ 1178.29=P(1+0.09\cdot 1)\implies 1178.29=P(1.09)\implies \cfrac{1178.29}{1.09}=P \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 1081=P~\hfill[/tex]
