Respuesta :

When A is added to twice B, the result is 21
[tex]a + 2b = 21[/tex]
When B is added to twice A, the result is 18
[tex]b + 2a = 18[/tex]
From the first equation;
[tex]a = 21 - 2b[/tex]
Substitute the value of a in the 2nd equation
[tex]b + 2(21 - 2b) = 18[/tex]
Simplify
[tex]b + 42 - 4b = 18[/tex]
Collect like terms
[tex]b - 4b = 18 - 42[/tex]
[tex] - 3b = - 24[/tex]
Divide both sides by - 3
[tex]b = \frac{24}{ - 3} [/tex]
[tex]b = 8[/tex]
Substitute the value of b in the first equation
[tex]a + 2b = 21 \\ \\ a + 2(8) = 21[/tex]
[tex]a + 16 = 21[/tex]
Simplify
[tex]a = 21 - 16 \\ \\ a = 5[/tex]
Therefore, A is 5 and B is 8. Hope I helped? ☺️
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