Answer:
502 g
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 127.91 253.81
2HI ⟶ H₂ + I₂
m/g: 506
(a) Calculate the moles of HI
n = 506 g HI × (1 mol HI/127.91 g HI)
n = 3.955 mol HI
(b) Calculate the moles of I₂
The molar ratio is (1 mol I₂/2 mol HI)
n = 3.955 mol HI × (1 mol I₂/2 mol HI)
n = 1.978 mol HI
(c) Calculate the mass of I₂
m = 1.978 mol I₂ × (253.81 g I₂/1 mol I₂)
m = 502 g I₂
