Answer:
This is 6x.
Step-by-step explanation:
f(x) = 3x^2 + 2
The differential coefficient (f'(x)) is the limit as h-->0 of [ f(x+h)-f(x)]/ h.
f'(x) = [3(x + h)^2 + 2 - (3x^2 + 2)] / h
= ( 3x^2 + 6hx + 3h^2 + 2 - 3x^2 - 2) / h
= (6hx + 3h^2) / h
= 6x + 3h
As h approaches very close to 0 we can neglect the 3h.
so f'(x) = 6x (answer).
