Respuesta :
Answer:
real and irrational roots
Step-by-step explanation:
The discriminant is b^2 -4ac
Where ax^2 +bx+c
a =3 b=0 and c =-10
b^2 -4ac
0^2 -4(3)(-10)
120
Since the discriminate >0, we have 2 real roots
Since 120 is not a perfect square, we will have irrational roots
The 120 is not a perfect square so the roots of the equation are irrational.
Given
The given quadratic equation is;
[tex]\rm 3x^2-10=0[/tex]
Discriminate;
Discriminate is helping us to determine the nature of the roots of the quadratic equation.
The discriminant is defined as the;
[tex]\rm Discriminant = b^2-4ac[/tex]
From the given equation the value of a = 3, b = 0, and c = -10.
Substitute all the values in the equation
[tex]\rm Discriminant = b^2-4ac\\\\\rm Discriminant = (0)^2-4\times 3\times (-10)\\\\\rm Discriminant = 0-(-120)\\\\\rm Discriminant =0+120\\\\\rm Discriminant = 120[/tex]
The value of the discriminant is [tex]\rm D>0[/tex].
Hence, the 120 is not a perfect square so the roots of the equation are irrational.
To know more about Discriminate click the link given below.
https://brainly.com/question/15884086
