Question

If a and b are the two values of t that satisfy the equation t^2 − t − 6 = 0, with a ≥ b, what is the value of a − b?


A. 5

B. -5

C. 1

D. -1

Answer 1

Answer:

A

Step-by-step explanation:

Solve $t^2-t-6=0$ by factoring the quadratic into $(x-3)(x+2)=0$. Using the zero product property, set each factor equal to 0.

x-3=0 so x=3

and x+2=0 sp x=-2.

The solution or a and b are 3 and -2. a=3. b=-2. So a-b = 3--2=3+2=5