Answer:The photon will emit light of [tex]2.30\times 10^{-2} pm[/tex].
Explanation:
The energy emitted by the photon,E : [tex]8.63\times 10^{-12} J[/tex]
Wavelength of the light emitted by this photon = [tex]\lambda [/tex]
[tex]E=\frac{hc}{\lambda }[/tex]
h = Planck's constant =[tex]6.626\times 10^{-34} Js[/tex]
c = speed of the light =[tex]3\times 10^{8} m/s[/tex]
[tex]8.63\times 10^{-12} J=\frac{6.626\times 10^{-34} Js\times 3\times 10^{8} m/s}{\lambda }[/tex]
[tex]\lambda=\frac{6.626\times 10^{-34} Js\times 3\times 10^{8} m/s}{8.63\times 10^{-12} J}=2.30\times 10^{-14} m=2.30\times 10^{-2} pm[/tex]
[tex]1 m=1\times 10^{12} pm[/tex]
The photon will emit light of [tex]2.30\times 10^{-2} pm[/tex].
