Question

Write as a product of 2 binomials and a monomial (factor out as much as possible from each binomial). (14x+21y)(6ab–3a)

Answer 1

Answer:

$3a(14x+21y)(2b-1)$

Step-by-step explanation:

Given, $(14x+21y)(6ab-3a)$

$(14x+21y)(6ab-3a)=(14x+21y)(3\times2ab-3\times a)$

$3$ and $a$ are common factors in second factor

$(14x+21y)(6ab-3a)=3a(14x+21y)(2b-1)$

Hence, the product of two binomial is written in two binomial and a monomial.