Question

What is the exact value of the exponential equation 17+e7x=33 ?
b. x=ln16 /33
c. x=ln16 /7

Answer 1

Answer:

c

Step-by-step explanation:

using the law of logarithms

log$x^{n}$ ⇔ nlogx

given 17 + $e^{7x}$ = 33 ( subtract 17 from both sides )

$e^{7x}$ = 16 ( take the ln of both sides )

ln$e^{7x}$ = ln16

7xlne = ln16 ← lne= 1

7x = ln16 ( divide both sides by 7 )

x = $\frac{ln16}{7}$ → c

Answer 2

Answer:

hello :

e^7x = 33 - 17

e^7x = 16

7x = ln16

x= ln16/7 .... ( answer : c )